Tempic field energy does not travel the circumference of the ring in a curve but moves straight between resonating points via the Tempic propagation path. The angles it leaves and enters node points is governed by the wheel of 24. It does not move as a circular wave in space but a longitudinal compression. This realization is key.

The angle is the angle that results from running lines through two node points that are adjacent for any polygon we choose to work on the tube.

The Fractal is the distance between these two points that the tempic field will be vibrating across, the air distance, not the copper curve distance, just as we discovered to be the case for vibrating up spheres in AFH document.

[This can now be calculated with the Windows calculator accessory using scientific mode which has sin and cos function.]

This tunning will result in 2 directions of the wheel of 24 shifting to the same frequency., and will lock in the isotope line in the copper tubes.

The tube will establish a coherent torsion field in 2 dimensions and sustain it. The standing isotope line that normally runs to the longest distances in copper will now be broken up into two 90 degree vibrating systems, both at mass resonance and coupled together via the wheel of 24, namely the 90 degree spokes.

In the matrix document there are a great number of lengths that will vibrate up with out matching the diameter to the length. These are linear resonance effects. They are either powered externally, or from the materials atom or crystal molecule levels, or from vibrations all around us already from the earth. The tubes here are generating their own vibrations from within the mass field, independent of any external vibrations. Power source is the tube itself as a coherent vibrating mass field.

The shorter tube pictured at the top of this document is diagrammed here. We cut the tube to resonate on the same Fractal as the ring at 90 degrees.

Theory behind this is from platonic vibration. All node points of the sphere vibrate outwards and inwards in sync, at precisely the same time. The waves then push the nodes to equidistant points of the surface. These are the only ones to survive and not cancel.

Calculations

Fractal Length = Diameter * ( sine (1/2 the angle))

Median Diameter of the the copper pipe = 1.078"

Angle = 360 / 4 = 90

Fractal Length = 1.078" x sin 45 = .762261

1x = 0.76221"

2x = 1.5245"

3x = 2.2867"

4x = 3.049"

5x = 3.8113"

These tube lengths will match the wavelength to produce 4 standing nodes on the circumference of the tube. The 4x will perfectly match the squares perimeter, and at this point both will be balanced.

A minus 1x should pull on the fabric of space one direction and a +1 segment should push the other direction.

The other configuration would then be a 5X 4N tube and one may feel a sensation of levity around it???

1x (0.76221") / 4 = .19055"

3x (2.2867") -1/4x( .19055") = 2.09615"

(Nodes should become 4x denser.)

1x = 3.049"

2x = 6.098"

3x = 9.147"

4x = 12.196"

This tube will cancel two fractals and quadruple the energy nodes.

3x (9.147") - 1x ( 0.76221") = 8.38479"

1x = 12.196"

2x = 24.392"

3x = 36.558"

4x = 48.784"

This tube will cancel three fractals and lengthen the tube again.

3x (36.558") - 1x (3.049") - 1x (0.76221") = 32.77679"

Now we can increase the node count one more time by clipping the smallest fractal we have calculated for a total of 4 canceling octaves.

32.77679" - .19055" = 32.58624"

[If you can work this accurate at that length, the gains should be extremely strong. Node count will quadruple again over the whole length of the tube.]

Study of the Light rods shows how energy acts between the Electron Vibration E [outer world], and the Nuclear Mass Vibration N [Weight], in the diagram above.

Where the Nuclear mass, sensed as a radiant torsion field of light, goes into highest vibration, the Tubes become still points and pressure drops. They can even be mounted on these node points and it will not dampen the vibrations. The dots in the graphic above show the point of mass vibration, or "light nodes."

There is a 90 degree phase shift in the two vibrations. Vibration moves from inside to outside down the light rod every 1/2 segment length, and back to center of mass on the next 1/2 segment.

We feel the "nodes" only where the nuclear vibration is maximum. We feel the "pressure sensation" where the electron vibration is maximum and hitting our outer world hardest.

Nuclear vibration operates to cancel Electron shell vibration, they act in opposition to one another, and this is the stabilization system of the atom. Also the reason for back EMF in electronics.

Note that off the ends it is the nuclear vibration that is peaked and the energy that is bouncing back, where on the ends the outer electron shells are at "still point."

This is the duty of the odd segmented Light rod lengths, and the 111 cutting technique, which can cancel selective octaves of the wave also.

Note wave shown above is a sine, but represents the amplitude and trimming of a longitudinal compression vibration running parallel to the rods length, and spiraling down it. Compressed tightly at the peaks of the chart above.

If one could see such a wave, they would actually see light being emitted off the single dots, where the nucleus is vibrating the strongest, from a tiny single point. This is the point of collision of the longitudinal wave bouncing off both ends of the rod and going radiant in all directions of the wheel of 24..

Canceling can also be done using the JC power supply setup with the reversed diodes to extract the torsion field waves from the EM flows. If the phase of a cancellation of opposing torsion fields is altered correctly, the electron shells are slightly released, back EMF will drop and the machine gets lighter.

As we cancel the self correcting effect of the atoms nucleus, it will try harder to expand its vibrational field to correct the distortions, and the field will expand outwards of the device raising a torsion field with layers that mirror electron shells.

When using a single tube as a powering source for platonic vibration, you can only cut the "length" to cancel. The ring cannot be driven to an odd multiple polygon.

In order to cancel the ring, one must add a second tube. This can achieve cancellation of the nuclear mass vibration in 3D space. Very probably over 3 or 4 octaves.

[Diagramming the vibrational field.]

The rings that hang in space around a Joe Cell follow the pattern of the electron shells. They also follow the pattern of the Light rods as shown by the ruler in the expanded rings above. The rings can be palmed to discover the distance between them is fixed.

What holds energy in the orbital rings is vibrational pressure due to phasing along the rings. This is a compression of space as combination of crossing waves forming high pressure zones and low pressure zones. Electrons will be sucked into the low pressure areas by the vacuum of space, given vector, organized, and then propelled along into layered orbital shells, by oppositely spinning waves on each side.

[I have actually stepped through one that was approximately 8 feet high. I smelled the ionization of the electrons collecting, and felt the weak charge raise the hairs on my arms.]

Above is shown a 4x or 4 Segment layered ring built by a 4x fractal system similar to the one on the tube we diagrammed above.

The spin forces running outwards and inwards of the concentric tubes along vibrational nodal points run through one another and set up canceling at the surfaces of the boundary. The boundary is the point where arrows above collide with one another.

.

Because there is a 90 degree phase shift between the Electron vibrational areas and the Proton areas we can expect the same in the external field. The boundary acts exactly like a light rod. The light rod has an EM point at fixed distance from the Nuclear Light node position. This can be measured using an AV plug in strong JC systems.

If we set up the tubes to cancel nuclear vibration vertically, outer electron shells will now vibrate up our tubes. We must set up the gaps to also cancel to achieve 3D compression on the nuclear level, and then increase the nodal count by trimming 1x segments off on both the height of the tubes and the diameter of the gap between the tubes. You can see there will be a host of possible methods, and a host of manipulations possible from phasing, one or both in different directions of compression or expansion.

Joe Cell is about "inflow" or compression, and creating a vacuum at the center of the cell. I will focus on that goal. We could cut shorter of the 1x lengths by higher fractal dimensions to increase node count on the outer tube of the cell. Longer on the inner tube to create expansion inside contraction. This is one possible pattern alternating along the tubes. however a central single node is better for pulling the zero point off balance strongly.

The cell represents the Proton Neutron layers of the atom, the electron shells will all be external. We will cut all outer tubes shorter and use negative charge at center on a single longer tube to start the interaction. Center tube will go slightly expansive, outer tubes will contract around it.

If all the tubes are set up with a 12x fractal system, we can cut off one segment of 1/12x and boost the node count tremendously [144x] only at 11 or one octave.

Center tube goes to 13x, outer tubes go to 11x, the tube will have 12 N nodes manifest around them all and be able to be aligned very precisely.

The cell will have 1/2" gaps [center of tubes meat] inter node distance. This is fixed for most JC geometry due to tube manufacturers.

Diameter will expand by 1" on each tube so fractals will also have a doubling per tube.

Cell should have odd number of tubes including can. This will set up a canceling fractal vibration in 3D. 3 or 5 total tubes.

Fractal Length = Diameter * ( sine (1/2 the angle)) [All the segment lengths use this formula]

12 nodes on all tubes

1" tube Fractal length = .2588" [1/4" +] [1.931 segments per 1/2" gap]

2" tube Fractal length = .5176" [1/2" +] [.9659 segments per 1/2" gap]

3" tube Fractal length = .77645" [3/4" +] [.6439 segments per gap]

4" tube Fractal length = 1.0352" [1" +] [.4829 segments per gap]

5" tube Fractal length = 1.294" [1 1/4"+] [ .38637 segments per gap]

One can now identify the problem with JC geometry, a slight increase in nodal length over the tubes gaps.

This difference can only be corrected by using different node counts on tubes where fractal comes out to be closer to 1/2".

This is exactly what my sensing revealed as well but I did not have the reason at the time.

Also note on the 3" and 5" segment gaps are way off.

If you have experience with Joe Cells you may have recognized the problems that develop around tube 3 in particular.

If there is a reversal of polarity, it may be that tube three is trying to reverse the phasing on tube 2x away from it.

One must start at the center and slowly work the voltage on each tube to get this flipped back until the nodes start to hold better in the tubes around number three.

Here is one solution, that looks much better.

Target Gap = .500"

6 nodes on tube 1

1" tube Fractal length = .5 [1/2"] [1 segments per 1/2" gap]

12 nodes on tube 2

2" tube Fractal length = .5176" [1/2" +] [.9659 segments per 1/2" gap]

18 nodes on tube 3

3" tube Fractal length = .5209" [1/2" +] [.95979" segments per gap]

24 nodes on tube 4

4" tube Fractal length = .5221" [1/2"+] [.95766 segments per gap]

30 nodes on tube 5

5" tube Fractal length = .5226"

It would appear adding 6 nodes per tube establishes a slow climb from 1/2" moving up slightly by a few hundredths of an inch error in the gap.

6 nodes on tube 1

1" diameter

7x = 3.5"

9x = 4.5"

11x = 5.5"

13x = 6.5" ***

15x = 7.5"

17x = 8.5"

12 nodes on tube 2

Length = [11 * .5176"] = 5.6936"

18 nodes on tube 3

Length =[11 * .5209""] = 5.7299"

24 nodes on tube 4

Length =[11 * .5221" ] = 5.7341"

30 nodes on tube 5 can

Length =[13 * .5226" ] = 6.7938"

Now measure the mean diameter of your actual tubes, and recalculate accurate lengths to the nearest .001" for each one separately using these node counts.

Your gaps will come out close, but not perfect. .02" off, but your nodes should now becomes much stronger and all cells should be consistent.

Fractal Length = Diameter * ( sine (1/2 the angle))

24 node systems have an angle of 15 degrees. [Wheel of 24]

Target gap distance = .250"

6 nodes on tube 0 Sample Cell Drift Diameter .250" Tube

1/2" tube fractal length = .250" 25x = 6.25" [1x Longer] 0 0

12 nodes on tube 1

1" tube Fractal length = . .25881" 23x = 5.95263" [1x shorter] +.00881" 1

18 nodes on tube 2

1.5" tube Fractal length = .26047" 23x = 5.99081" *** +.01047" 2 *

20 nodes on tube 2

1.5" tube Fractal length = .234651" 23x = 5.396989" -.015348" 2

24 nodes on tube 3

2" tube Fractal length = .261052" 23x = 6.004196" +.011052" 3

26 nodes on tube 3

2" tube Fractal length = .24107336" 23x = 5.544687 *** -.00892644" 3 *

30 nodes on tube 4

2.5" tube Fractal length = .261321" 23x = 6.010383" +.011321" 4

32 nodes on tube 4

2.5" tube Fractal length = .2450428" [ 2x correction factor] 23x = 5.6359844" *** -.0049572" 4 *

36 nodes on tube 5

3" tube Fractal length = .261467" 23x = 6.013741" +.011467" 5

38 nodes on tube 5

3" tube Fractal length = .247738" [ 2x correction factor] 23x = 5.697974" *** -.002262" 5 *

42 nodes on tube 6

3.5" tube Fractal length = .261555" 23x = 6.015765" +.011612" 6

44 nodes on tube 6

3.5" tube Fractal length = .249687" [ 2x correction factor] 23x = 5.742801" *** -.000313" 6 *

48 nodes on tube 7

4" tube Fractal length = .261612" 23x = 6.017076" +.011612" 7

50 nodes on tube 7

4" tube Fractal length = .251162" [ 2x correction factor] 23x = 5.776726" *** +.001162" 7 *

Lots of choices there to make the tubes sing!

Notice the error creeping in [Drift Column] running .011" over on conventional progression, a correction factor of 2x can be used to compensate, especially up at the 4" tube.

Now stack them in Odd sums to get a length that will produce polarized tube and design a cell for trails.

Also notice that a number of these tubes do not match the wheel of 144. The interaction is an unknown at present, however these tubes will vibrate.

Example1

I want to fashion a 1" copper tube that has an actual diameter of 1.078" to its median thickness.

From the chart above 1" tube @ 23x = 5.95263"

1 / 1.078 = 5.95263 / X

1.078 * 5.95263 = 6.4169"

Example 2

Next I have a SS tube having 1" OD and .896" ID median diameter = 1" - (1" - .896" / 2) = .948"

.948 * 5.95263" = 5.643"

Note

These two tubes are very different in length, due to having slight different diameters.

If cut correctly they will both radiate a strong 1/4" fractal off all sides having 12 nodes on the ring.

I lay the calipers to touch over the end of the tube and then firmly on the node point, and these vibrate up strongly even without cutting them.

I slide a finger along the tube moving closer and away and note the main energy is on the 1/4" gap spacing. The numbers appear to be correct.

At 23x segment lengths, very small difference in diameter is additive.

This small difference translates to a tube that will not vibrate up of its own mass.

If care is taken to measure all your tubes ID and OD then find the median diameter, plan a chart like the one above and find the most accurate fractals.

I believe we can create cells that will never generate reversed polarity gaps.

Also they should not "bang the head" from a mismatched distance reversing phase a couple tube down the line.

They may never go dead over time, due to having strong radiant fields???

Tube Mass Center Angle Gap Odd Actual Odd Actual

Number OD - Thick = Mean Diameter Nodes Degrees Segment Length Segment X Tube Length Segment X Tube Length

1 1.00" .050" .950" 6 60 .475" 11x 5.225" 13x 5.941"

4 90 .671"

2 2.000" .050" 1.95" 12 30 .50469" 11x 5.552" 13x 6.561"

14 25.71 .43391"

3 2.994" .065" 2.929" 18 20 .50861"

20 18 .4581" 11x 5.040" 13x 5.956"

4 4.000" .065" 3.935" 24 15 .51362"

26 13.846 .47431" 11x 5.217" 13x 6.166"

5 5.000" .03" 4.97" 30 12 .5195"

32 11.25 .4871" 11x 5.359" 13x 6.333"

34 10.5888 .45857"

OD - Thickness = Mean diameter

Angle = 360 / Node Count

Fractal Length = Diameter * ( sine (1/2 the angle))

Notice that on tubes with perfect outer diameter, the gap comes out smaller between all tubes on the mean diameter.

The goal is now to shoot for .475" rather then .500" on all tubes.

It is possible however to add one to the outer ring to see if a self sustaining voltage might assist the rest of the cells process.

8.245"

5.589"

2.931"

14.195 cm = six segment octave

Torsion rod 14.195 cm - .075 volts constant

EM rod 17.57 cm tube - .136 volts constant

Same formula, for any tube. You will generate a node every 2.5 degrees around the tubes circumference.

Fractal Length = Diameter * ( sine (1/2 the angle))

Angle = 360 / 144 = 2.5 degrees

Sine (1.25) = .02181488

Fractal length = Diameter * .02181488"

Now start stacking 143 of these, or 145 of them to create a resonating length tube and see what pops out.

[Keep some gloves and a hammer handy if you have to smash the tube shortly after it fully charges!]

But remember its only vibration. LOL!

I have only done this using calipers near a 6N tube, so I do not know the outcome for sure, or how high the vibrations will charge up on a tube.

The SS calipers lit up pretty nice however at 143x gap.

My personal thanks to Smokey of c_s_s_p group for assisting the study the long tubes of Reich, and TJ Constable.

Continued thanks to Bernie as well, for sharing his experience with the Joe Cells.

Levitation Site Index

[Public Domain]

Dave L

c_s_s_p group

7 / 29 / 2009