The Vector Equilibrium

file / VE-333.html

2016 - 11 - 23


VE Drawing

 S1 = 29.613 cm
A1 = 379.73 cm sq
A2 = 876.94 cm sq
 

VE consists of 2 basic forms, triangle and square, with common side length, assembled to produce a single point center with 12 equidistant connections in 3D space to the outer structure of the form.


Beginning with the basic concepts under scrutiny:

1 - The vector equilibrium is a form, sustained by the background field, and found at the heart of all matter at it's smallest inner point of manifestation

2 - The background field is resonant at 333000 Hz - and this is what powers all matter and energy forms present on earth

3 - The "A" field in electronics is an area, as shown in coils. The energy can be tapped at any point inside a coil of wire and is contained inside the loop with equal intensity at every point inside the loop.

4 - The frequency of the "A" field is equal to the area inside the circle, triangle, or square. The larger the area the higher the energy inside the form and the higher the frequency of the mass vibration that is coherent.

5 - We can dimension a Quantum Vector Equilibrium such that the area of the triangle times the area of the square will resonate directly with the background field. This form will couple to the inside of all matter and self power.

6 - The metric system is derived from the properties of water, and thus can be used more efficiently for all calculation, accessing the root background field of space / time, and time / space.

7 - If we extract the correct parameters of the Vector Equilibrium, at fractal dimensions where it couples, we can use this for health application, to create an access to all points on the body as one, and balance the inflow / outflow ratio to improve health.
     Modification of size can be done using geometric fractal expansion or contraction.



Derive the dimensions at cm levels for a quantum VE structure that will power off the background field at 333000 Hz.

Diagram 1

Split the background field into two factors, that will separate inflow and outflow.



Derivation

A1 * A2 = 333000   [inflow outflow separation factors]
S1 = square root (A2)
L1 = S1 * sin(60)
A1 = L1 * S1 / 2
A1 = S1 * sin(60) * S1 / 2
A2 = S1 * S1
333000 = S1 * S1 * S1 * S1 * sin(60) / 2
333000 = S1^4 * sin(60) / 2
666000 / sin(60) = S1^4

S1 = Root 4 (666000 / sin(60))
S1 = 29.613238 cm
S1 = 296.13238 mm

A1 = 379.72783 cm^2  Hz
A2 = 876.94387 cm^2  Hz

A2 / A1 = 2.3094 Frequency Ratio




Geometric Reduction

S1 = 29.613238 cm             A1 = 379.72783                 A2 = 876.94387

S1 / 2 =  14.806619 cm       A1 / 4   =  94.932               A2 / 4   =  219.236    
S1 / 3 =  9.8710793 cm       A1 / 9   =  42.192               A2 / 9   =   97.43820
S1 / 4 =  7.4033095 cm       A1 / 16 =  23.733               A2 / 16 =   54.80899  




Health Tube - VE / RA - Whole Body Energy Balancer

[Ra Tube is a catch all group of resonant fractals that peak their energy center around 6 inches or 150 mm]
[VE is the vector equilibrium form at the core of all matter]

Material - Any Diamagnetic Metal such as Aluminum or Copper
Length     148.07 mm



Quadrature Field From the Quantum VE

Quadrature Field

S1 = 29.613238 cm
S2 = 41.879443 cm
Frequency = 1753.887729 cm sq



Quadrature Spin

Spin

Find the diameter of a circle with area 1753.887729 cm sq
A = Pi  * r * r
Diameter S3 = 2  * sqrt (Area / Pi)


Diameter S3 =  47.25589 cm
S3 / 2 = 23.62794 cm sq
S3 / 4 = 11.81397 cm sq


Find the diameter of a circle with area 876.9438654 cm sq 

S3 * sqrt 2 = 33.41496 cm


Triangle Spin

Tetrahedron Spin

 
Find the diameter of a circle with area 379.72783 cm sq
A = Pi  * r * r
Diameter S4 = 2  * sqrt (Area / Pi)

Diameter S4 = 21.98828 cm
S4 / 2 =  10.99414 cm

Hex Spin

Hex Spin


Find the area of the Hex form
Find the diameter of a circle with Hex form area


Area = 6 * 379.72783  cm sq
Area = 2278.36698 cm sq


Diameter = 2  * sqrt (Area / Pi) 

Diameter 53.860 cm
Diameter / 2 = 26.930 cm
Diameter / 4 = 13.4650 cm

Square Triangle Angle Differentials

Differentials

S1 = 29.613238 cm
L1 = S1 * sin(60)

In = 20.9397214 cm
Out =  24.179107 cm 
  
 L1 = 25.645816 cm
L2 = 14.806619      
L3 = 8.548605 cm

Arc sin (L3/L1) = 19.4712 Deg      
 Arc sin (L2/L1) = 35.2644 Deg      
Arc sin (In/L1) = 54.735612 Deg   
Arc sin (Out/L1) = 70.528778 Deg


Inner Differential Angle  =  54.735590 Deg  
Outer Differential Angle  = 125.264390 Deg   




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