Applications of the 333 NMR chart

Reference: Walter Russell

6.66 meters = 21.85 feet

33 degree angles

16.5 degree slope

1/50 scale drawing

6.66 meters = 21.85 feet

33 degree angles

16.5 degree slope

1/50 scale drawing

Single Cone Dimensions:

Height 3.33 meters

Diameter 1.9727818434 meters

Side 3.4730198211827723274 meters

333 / 51.118 = 6.5143393716499080558707304667632 [non repeating decimal sequence]

(1H / 4) / 2H

83.25 / 51.118 = 1.6285848429124770139676826166908 [self sustaining vibration compression ratio]

2H / 1H

51.118 / 333 = 0.153507507507507 ... [Repeating decimal 507]

2H / ( 1H / 10)

51.118 / 33.3 = 1.53507507507507 ... [repeating decimal 507 and self sustaining ratio on 10th subharmonic]

3H / 222 [Source field 1.85 mm fractal group 120x]

355.191 / 222 = 1.599959459459459 ... [ repeating decimal 459 and self sustaining ratio off 12x harmonic of source field]

3H / 1H

355.191 / 333 = 1.0666396396396 ... [repeating decimal 396]

1H / 3H

333 / 355.191 = 0.937523754824868873366723 [non repeating decimal]

Deuterium receives a near Phi ratio push off (333 / 4) of Hydrogens vibration resonance, the background field. It becomes heavy.

Deuterium now stabilizes against (333 / 10) with a near pi/2 ratio.

Is this the formula to create mass?

(333 / 4 ) / 1.6285848429 = 51.118

That Phi formula crosses the pi/2 harmony formula

(333 / 10) * 1.53507507507 = 51.118

Both formulas come out to the same frequency 51.118 from two directions

Cone Height 51.118 cm

1/10 scale drawing [1 cm = 1 mm]

Construction Data:

Angle at apex 33 degrees

Slope Angle 16.5 degrees

Vibration Data:

Cone Height 51.118 cm

Cone Diameter 30.284 cm

Cone Side Length 53.313 cm

Alternate [although it does not feel right to me the sides will resonate and may precess]

Cone Height 49.0129480 cm

Cone Diameter 29.03659 cm

Cone Side Length 51.118 cm

Vibration resonance frequency 2H = 51.118 kHz

EM resonance frequency 1H = 333 kHz [1H = 333 kHz at self sustaining ratio .153507507 = 51.118 kHz]

I now believe by correcting the dimensions of the dual cone experiment, we may be able to achieve the correct background field resonance.

The "Bashar channeled dimensions" appear to be ever so slightly different for a Deuterium vibration resonance.

Dual Cone Calculation per Bashar

Height 49.7220 cm

Diameter 29.45668 cm

Side 51.8575 cm

Scale - mm - Drawing

Cone Height 86.769 cm

Cone Diameter 51.4042966 cm

Cone Side Length 90.4956326 cm

NMR resonance couples from the center of mass of an object as a coherent field that is balanced to each side.

The dual cones provide a path between the compressed center of gravity position and the expanded electromagnetic fields we experience from the outside of atoms.

The mass field centers as a coherent quantum field, and is the coupling point for gravity. Gravity is a collective field, that always works from one center location, the mean shortest distance from all mass present.

Larger devices can be designed to harness similar geometry, at larger fractal dimension, as a single atom, and if the theory is correct, they should then exhibit the same self sustaining fields that an atom does.

2 - 19 - 2016

[Parallels in the Metric and Imperial Measuring systems]

While modifying the spreadsheet for the "dual cones turns" to reflect corrected EM resonance values, from the third builds measurements, a pattern emerged.

If a 33 degree dual cone is built to a height of 66.6 cm.

A wire length of 666 feet wrapped down it, should make it electrically resonant at 197 kHz

The VOP will become 0.528 as the two cones are merged together.

y = 19.727818 = 1/2 the diameter

Vibration on end of cone should resonate at harmonics of 19.7 or 197 kHz, so we have an EM wire length matching a supportive vibration resonance.

Drawing 1/10 scale

Height 66.6 cm

Diameter at base 39.455636868 cm

Side Length 69.460 cm

Wire length 666 feet [202.9968 meters ~ 203 meters]

[ 2mm diameter wire with insulation 666 feet long, spreads to 2.155 mm when wrapped and epoxied ]

Vibration Resonance 66.6 kHz

EM Resonance 197 kHz

A full Walter Russell system would have a length of 2x = 66.6 x 2 = 133.2 cm [QEG frequency] = 1.332 meters

The lengths all vibrate up on the caliper at mm distances or 1/10 or 1/X0 of actual.

66.6 mm

39.46 mm

69.46 mm

20.30 mm

133.20 mm

If the wire is located accurately, the wire will be hit from all directions with a set of crossing vibrations.

Every dimension is likely critical to a success. Best Guess.

Right click and save [openoffice org] file to your computer to then open it.