3SD - UTRON - Hamel Cones - Searl Disk
Matter is based on structure having strength, and always reduces to triangular form.
Fields are based on quadrature structure 90 degree and ~ 45 degree angles.
The background Aethers structure is based on a 12x octave system.
Diagram 1
The diagram is representing two concentric tubes shown as black circles.
The inner tube is being injected with a mass vibration establishing 3 nodes around its circumference shown in violet.
The outer tube is being injected with a mass vibration establishing 4 nodes around its circumference shown in blue.
This creates 7 nodal points total.
If we stand beside, or outside the tubes, then rotate the inner tube one time, there will be 3 pulses as the nodes pass by us.
If we instead rotate the outer tube around one time, there will be 4 pulses as the nodes pass us.
So relative to the observer outside the tubes, there is a difference in sync clock rate for 1 rotation of each tube.
If we rotate both tubes, 1 revolution, we should feel 7 pulses with respect to us.
If two corners are aligned with us and center point, as they pass, we will only feel 6 pulses and one of them will be more intense.
Good palming ability, should be able to locate these points where there is a shift from 7 to 6 pulses, felt as a change in one of the pulses intensity.
Rotation
Diagram 1
See diagram 1: The inner tube is now rotated CCW, or to the left at the top, and the outer tube is kept stationary to us.
As vibrational nodes cross along a line to center, they will interact between the two tubes and the common center of gravity.
The first crossing will be the points labeled 1, the shortest distance. Next will cross points 2 and then points 3.
The points of crossing in real time will appear to be moving CW.
Diagram 2
After 90 degrees of rotation on the inner tube, we have generated 3 cross pulses in real time, on points 1 2 3 of the square in space.
The pulses move the opposite direction of the triangles rotation, on the square geometric form in space.
The next sequence will be triangle 1 crossing square 4, and the count will be 4 1 2 [in space] or 4 5 6 [in time] if you label over them.
We have now completed only a 180 degree turn of the triangle, and are 1/2 the way to 1 revolution,
while the pulsing on the square seems to have reached 1.25 rotations around it.
A full revolution of the triangle CCW will then produce pulses 1 2 3, 4 5 6, 7 8 9, 10 11 12 in time,
Moving CW on the square producing pulses 1 2 3 4, 1 2 3 4, 1 2 3 4 in space,
or 2.75 revolutions in space, with the next pulse landing on 1 for 3 revolutions.
So for 1 revolution of the triangle CCW, the squares pulsing sequence [energy field] has completed almost 3 revolutions CW.
The energy field is accelerated to 3 times the rate of physical revolution, and reversed in spin direction.
If we spin the outer tube and keep the inner tube stationary, the space time parameters reverse.
We will see pulsing in space as 123,123,123,123 positions on a triangle form, with 12 pulses in time.
4 revolution [or 3.666..] of the triangle moving backwards for one revolution of the square moving forwards.
With the triangle stationary, we gain one revolution of the field motion.
Now if both are rotated in opposing direction we should be able to extrapolate
an energy gain of 12 rotations of the energy field, for 1 revolution of each tube.
The 12x octave structure of the Space Time field, in motion.
Seeing Into Other Density Realities
The result offered from spinning both in opposing direction, is first a doubling of the energy pulses with respect to us, but also an adjustable function of the "perception field" in Space Time.This opens the door to pineal manipulation and tuning, using a machine. All it does is provide the pineal screen with a carrier, to tune in other realities, on other layers of the earth sphere.
You do not have to be inside the circle to gain the perception of the tunned realm. You can slide your consciousness inside it without taking your body there.
If one of the radials of energy crosses your pineal area, you can see the realm being tunned and converse with the beings there, if any are truly present.
Everyone would see the same realm, if tunned technically the same on the device.
So the device must have accurate calibration and readout of rates of revolution for each tube,
and the same for the energy bubbles motion, being overlapped on your pineal area.
This is the tool, "They" want us to create first.
It will shift our perception of ourselves.Only after charting our own earth sphere reality, and comprehension of what it actually is, should we pursue over unity,
or Source energy devices to power our world.
With the creation of this device, anyone can then look into the other realms for them self, and the doubts will be ended on many levels of our belief system.
That is at present the "message," being received by me.
The device will teach a person how to "see" all that is actually here.
Pineal Transducer Development
Producing a 3D field to overlap on the pineal using "palm touch", and "sliding" ability.An Aluminum hand grip for the left hand or for both hands, routed up into the dual ring system, at the center of mass position.
A longer hand grip will allow, two people to compare what they both are seeing simultaneously.
UTRON uses only one electromagnet because each cone has its own motor, and can be adjusted in RPM independently for even or odd nodal counts.
Because we only desire a rotating vibration field on each ring, we must achieve a rotating nodal pattern using coils of copper and iron design on a stationary ring.
Next is to design two rings that are concentric, then position the hand grip tube in the center of them, extending downwards to the base.
Rings of both Aluminum or Copper can be tested, and various coils for pulsing can also be tested on them to establish the correct nodal rotations.
One must develop a sense for even or odd node counts on the rings, then a calibration for rotational RPM of the nodes motion.
As the two are then used simultaneously, first an even odd relationship should be the starting point. Odd inside even, even inside odd ...etc...
Power Generation
It is possible to produce electricity, without using magnets, but by using only mass vibrating copper coils and motion.In general strong vibration fields reduce the electron EM noise floor, however if the positive energy flows linearly, electricity can be the result.
After building an over sized Lathem Star Link system, I noticed that when touching the two kinds of coils together,
a scope trace would show consistently, very high voltage spikes happening during connection and on release.
Lathem Star Link
Note that in the above examples [last section] the ratio between the diameters of the two circles is the square root of 2 = 1.41421356 x.
This is also the peak value of an EM sine wave with voltage peaking at the outer circle, but the power level is represented by
the inner circle, which is spinning in copper medium, and is the RMS value of 0.707106 x of the outer circle.
[The power is in the vibration and not the voltage peaks.]
In order to force the inner triangle circles nodes to spin, we need to add two things.
1 - A gravity gradient towards the center [phi moving upwards in frequency]
2 - A way to use this to cause the copper mass field to go into an electrical rotation [sqrt 2]
In order to generate a rotating field of electricity from copper, one needs the positive nuclear mass to go into a rotation.
Since the electron shells of copper are not free to rotate as in iron, we are left with only the dark nodes to create a generator system.
Spurling Fractals - Dark Nodes
Dual Copper wire study
2nd scan:
1x - 3.43333"
2x - 6.8666"
3x - 10.3"
4x - 13.7333"
5x - 17.1666"
6x - 20.6"
7x - 24.0333"
8x - 27.4666"
9x - 30.9"
10x - 34.3333"
11x - 37.7666"
12x - 41.2"
13x - 44.6333"
Only rational lengths are 3 6 9 ...
[note this pattern is well suited for a triangular system]
Primary Element Design
Diagram 3
[A Copper Coil]
If we can set the "dark nodes" inside copper wire to rotate and slide up a coil, it may likely produce electricity on the electron shells as counter EMF.
We construct the center coil based on a triangle matrix of the Spurling fractal, and if it rotates then EM should be available on the outer coil with a 4 point sqrt of 2 matrix on it.
Polygon formula
FS [one side of triangle] = Diameter [of circle] * sin (1/2 the polygon angle)
Solve for our Spurling dark node matrix copper coil diameter
Diameter = FS/ sin (1/2 the polygon angle)
Diameter = 3.43333 / sin(60 degrees) = 3.964467999 inches
Circumference = 12.454743542 inches
[Note this is the outer diameter of the toroidal core in my autotransformer, that I was able to create a field bubble with
which powered a light bulb when the cord was removed from the wall plug.]
Tensor Energy
Hendershot note - if we do this inverted the numbers get smaller:
Solve for an inner circle triangle with diameter of 1x Spurling fractal:Diameter = 3.43333"[1x] * sin (60degrees) = 2.97335 inches
Circumference = Pi * Diameter = 9.34105765 inches = wire length for one turn
Diameter x 2 = 5.9466500 inches
Circumference x 2 = 18.68195 inches
[The 2x is double this diameter, and we come out within .009 inch of the Hendershot basket weave coil diameter.]
15.08125 cm = 5.9375 inches Hendershots dimension
Hendershot Builds
Secondary Element Design
Diagram 4
[Concentric Copper Coils]
Further we must generate a gravity field inwards off the Spurling fractal so the field will tend to go into an orbital mass rotation.
We have some possibilities to consider experimenting with, and may reveal the nature of what EM is.
Here is the simplest solution, to set the dark nodes to motion.
EM
Sqrt 2 =========> <========== PHI
If we simply pit the root of 2 against phi we get a manageable gradient in dimensions.Phi / sqrt 2 = 1.14409877 x
phi * sqrt 2 = 0.87398398 x
Now calculate off the primary coil using the new ratios.
Possible Inner Coil
Diameter 2.59866 inches
Circumference 8.1639347 inches
Possible Outer Coil
Diameter 3.401807 inches
Circumference 10.68709257 inches
Both coils will interact with the primary coil, but possibly in different ways.
Containment
Using phi directly in a formula like this with the dark nodes is a very dangerous experiment, but more likely to succeed at power generation.In order to limit the danger, a containment coil or even a cylinder can be constructed to force the bubble inside to conform with a gravity pattern at the outermost layer of the device.
This may also act as a microwave shield???
Gravity
2/Pi ==========> <========== Phi
For this then we can use a standard weak gravity warp bubble formula.(2/pi)^3 * Phi^4) = 1.2672699 x
Diameter 3.768038 inch
Circumference 11.83764 inch
Experimental Data
There are several possible ratios to try, and we can use stainless steel tubes with caliper injection to test them out.1 - The root of 2 times phi as diagrammed above
2 - The ratios from the 925 Hz document
3 - Earth core 7.11 ratio Plasma to Gravity
The dark nodes are fixed in distance apart, thus on the copper element we already have a segment length from the chart above.
In order to set the dark nodes in copper into motion, we can set up the SS tubes with this offset.
The gravity bubble on the tubes will then be based on a different segment length then the dark nodes and interact with it.
We must have two layers for it to self sustain, as the ratio to the copper will not self sustain on a root of 2 jump.
Root of two is a way to tap energy from a self sustaining gravity field bubble.
The first experimental setup showing a single copper tube down the center of two stainless steel tubes, concentrically aligned.
The two stainless tubes will be injected with various gravity patterns using SS calipers, in hopes we can set the nodes in the copper to motion.
The next experiment is to see if we can create electrical activity, using the SS tubes at the center of a Hendershot basket weave coil system.
The gravity bubble will be at some ratio off the dark node segment length, and be set up for a strong effect.
Lastly we add some Aluminum rings where the Hendershot capacitor would be located.
Reference
Phi = 1.618033988749894890x Phi Closed Loop 1.617940
Pi = 3.1415926535897932
Pi/2 = 1.5707963267948966
sqrt2 = 1.414213562373095